Ooooooooh!! S**t!!

Started by R1Dude, November 12, 2006, 08:45:14 PM

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Prof

Fly Power - Fly Power x 18/100 = Rear Wheel Power

Fly Power x (1 - 18/100) = Rear Wheel Power

Fly Power x (100/100 -18/100) = Rear Wheel Power

Fly Power x (82/100) = Rear Wheel Power

Fly Power x 0.82 = Rear Wheel Power

So Fly Power = Rear Wheel Power / 0.82
"Plus this engine is probably one of the most volumetric engines going! It passes more air than a herd of cows eating vindaloo\'s" - courtesy of AtomicRex


normski

Quote from: DLN:eek: :)  is he that good with the rotaries then?

I will tell you without any bull ****, Pip G, at WGT is about as good as it gets! He is mustard Bloody hot mustart to, when it comes rotor engines. Pip always plays safe, WIll will not cut corners as his rep is second to none, He may not be the cheapest out but he is by far the best. 99.9999% of the time if recons anything on a rotory he is right! :Thumbsup!

Ricco_04

Drivetrain loss is an absolute and not a percentage.  For example a car said to have 20% loss :

200 bhp = 40Bhp loss
1000 Bhp = 200Bhp loss

Hope this is confusing! :spank  :Thumbsup!

D1 WTF

Quote from: D1 WTF293/0.82=357      
this just dont seem correct in anway, below would be the true figure surely (all be it with 17%)
293/100=2.93          2.93x18=52.7      293+52.7=345.7

i am confused, so which one of these is correct or is neither
IF YOU DIDN\'T CARE YOU WOULDN\'T BE LOOKING

R1Dude

Its looking good whatever the correct calculation is ppl:Thumbs-up  P.s I`m taking my engine out on sunday, not taken a rotary out before so any advice will be greatly appreciated:Thumbsup!

stylus350

Quote from: Ricco_04Drivetrain loss is an absolute and not a percentage.  For example a car said to have 20% loss :

200 bhp = 40Bhp loss
1000 Bhp = 200Bhp loss

Hope this is confusing! :spank  :Thumbsup!

If your saying that there is a reducing percentage of loss as power increases then I agree. I cant believe a 400 hub rx loses 72hp through the transmission when a 200 hub loses only 36. There is surely a point at which the loss becomes static to rising forces. What are transmission losses? If we can state the components and ways power is absorbed by the the transmission then maybe we can work out if these losses would increase infinately. I doubt very much that they do. I would need a lot of convincing.

D1 WTF

i am seeing pip tomorrow so i will ask him.
IF YOU DIDN\'T CARE YOU WOULDN\'T BE LOOKING

Jit

Quote from: R1DudeIts looking good whatever the correct calculation is ppl:Thumbs-up  P.s I`m taking my engine out on sunday, not taken a rotary out before so any advice will be greatly appreciated:Thumbsup!

its easy! just try and keep the loom attached to the engine as much as possible...make sure you get the car high enough in the air so you can undo the pressure plate

Ricco_04

Another example : you loose energy when your power goes through the gearbox.  This is the same gearbox that you use when you have say 100bhp more so why would the loss be greater - it\'s not (or so I believe?)

There are many things that affect transmission loss from tyre pressures to different oils etc etc.

Prof

Quote from: D1 WTFi am confused, so which one of these is correct or is neither

It\'s all about whether you take the 18% off or add it on.
 
18% of the Fly power will be more than 18% of the wheel power - that\'s where the difference is coming from in your example.
 
Hope that clears it up.
"Plus this engine is probably one of the most volumetric engines going! It passes more air than a herd of cows eating vindaloo\'s" - courtesy of AtomicRex


D1 WTF

Quote from: ProfIt\'s all about whether you take the 18% off or add it on.
 
18% of the Fly power will be more than 18% of the wheel power - that\'s where the difference is coming from in your example.
 
Hope that clears it up.

so which is correct/ surely there must be a correct way of doing it.
IF YOU DIDN\'T CARE YOU WOULDN\'T BE LOOKING

Prof

It\'s all about where you take 18% from.
 
The 18% is a loss, so it\'s 18% of the larger flywheel figure that you subtract.
 
By doing the calculation the other way, you are working out what 18% of the wheel power is, and then adding that on - that 18% is not as big as the 18% that would have come off if you follow me !
 
For example :
 
25% loss from 100 would be 75
 
If you did that calculation the other way round and said 25% increase on 75 - then you\'d be saying add 1/4 of 75 onto 75 - that will never be 100 - it\'s 18.75+75 = 93.75
 
By dividing by 0.82 you are doing the reverse of subtracting 18% from the larger figure - so it works backwards.
 
take the 100 example above :
 
100 - 25 = 75
 
Reversing this you would divide by 0.75 so 75/0.75 = 100 !
"Plus this engine is probably one of the most volumetric engines going! It passes more air than a herd of cows eating vindaloo\'s" - courtesy of AtomicRex


88GT-R

It will not always be a set %. Weight of rolling parts plays a big part in what power is seen at the wheels. Lighter hubs, brakes and wheels/tryes will show a \'higher\' figure at the wheels, where in fact the power made at the engine has not changed.

J

D1 WTF

i want to convert my figure which was done on dynopac, so therefore RWHP (as it is done at the hubs) figure to fly wheel hp.
how do i do that.    

ah hold on i finished reading your post, i kind of get it.
IF YOU DIDN\'T CARE YOU WOULDN\'T BE LOOKING

Ricco_04

When I had my car mapped at Pip\'s I got a FWBHP figure - or I assume so as its too high to be RWBHP! :D